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File src/diff.c part of check-in [36b96b8616] - Rework the merge algorithm. It now only works for text files. But, it no longer gets confused by line endings (\r\n versus \n) and it reports conflicts. by drh on 2007-11-16 20:42:31.

/*
** Copyright (c) 2007 D. Richard Hipp
**
** This program is free software; you can redistribute it and/or
** modify it under the terms of the GNU General Public
** License version 2 as published by the Free Software Foundation.
**
** This program is distributed in the hope that it will be useful,
** but WITHOUT ANY WARRANTY; without even the implied warranty of
** MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
** General Public License for more details.
** 
** You should have received a copy of the GNU General Public
** License along with this library; if not, write to the
** Free Software Foundation, Inc., 59 Temple Place - Suite 330,
** Boston, MA  02111-1307, USA.
**
** Author contact information:
**   drh@hwaci.com
**   http://www.hwaci.com/drh/
**
*******************************************************************************
**
** This file contains code used to compute a "diff" between two
** text files.
*/
#include "config.h"
#include "diff2.h"
#include <assert.h>


#if 0
#define DEBUG(X) X
#else
#define DEBUG(X)
#endif

/*
** Information about each line of a file being diffed.
**
** The lower 20 bits of the hash are the length of the
** line.  If any line is longer than 1048575 characters,
** the file is considered binary.
*/
typedef struct DLine DLine;
struct DLine {
  const char *z;    /* The text of the line */
  unsigned int h;   /* Hash of the line */
};

#define LENGTH_MASK  0x000fffff

/*
** Return an array of DLine objects containing a pointer to the
** start of each line and a hash of that line.  The lower 
** bits of the hash store the length of each line.
**
** Trailing whitespace is removed from each line.
**
** Return 0 if the file is binary or contains a line that is
** longer than 1048575 bytes.
*/
static DLine *break_into_lines(char *z, int *pnLine){
  int nLine, i, j, k, x;
  unsigned int h;
  DLine *a;

  /* Count the number of lines.  Allocate space to hold
  ** the returned array.
  */
  for(i=j=0, nLine=1; z[i]; i++, j++){
    int c = z[i];
    if( c==0 ){
      return 0;
    }
    if( c=='\n' && z[i+1]!=0 ){
      nLine++;
      if( j>1048575 ){
        return 0;
      }
      j = 0;
    }
  }
  if( j>1048575 ){
    return 0;
  }
  a = malloc( nLine*sizeof(a[0]) );
  if( a==0 ) fossil_panic("out of memory");

  /* Fill in the array */
  for(i=0; i<nLine; i++){
    a[i].z = z;
    for(j=0; z[j] && z[j]!='\n'; j++){}
    for(k=j; k>0 && isspace(z[k-1]); k--){}
    for(h=0, x=0; x<k; x++){
      h = h ^ (h<<2) ^ z[x];
    }
    a[i].h = (h<<20) | k;;
    z += j+1;
  }

  /* Return results */
  *pnLine = nLine;
  return a;
}

/*
** Return true if two DLine elements are identical.
*/
static int same_dline(DLine *pA, DLine *pB){
  return pA->h==pB->h && memcmp(pA->z,pB->z,pA->h & LENGTH_MASK)==0;
}

/*
** Generate a report of the differences between files pA and pB.
** If pOut is not NULL then a unified diff is appended there.  It
** is assumed that pOut has already been initialized.  If pOut is
** NULL, then a pointer to an array of integers is returned.  
** The integers come in triples.  For each triple,
** the elements are the number of lines copied, the number of
** lines deleted, and the number of lines inserted.  The vector
** is terminated by a triple of all zeros.
**
** This diff utility does not work on binary files.  If a binary
** file is encountered, 0 is returned and pOut is written with
** text "cannot compute difference between binary files".
**
****************************************************************************
**
** The core algorithm is a variation on the classic Wagner
** minimum edit distance with enhancements to reduce the runtime
** to be almost linear in the common case where the two files
** have a lot in common.  For additional information see
** Eugene W. Myers, "An O(ND) Difference Algorithm And Its
** Variations"
**
** Consider comparing strings A and B.  A=abcabba and B=cbabac
** We construct a "Wagner" matrix W with A along the X axis and 
** B along the Y axis:
**
**     c 6               *
**     a 5               *
**     b 4           * *
**     a 3         *
**     b 2       *
**   B c 1       *
**       0 * * * 
**         0 1 2 3 4 5 6 7
**           a b c a b b a
**           A
**
** (Note: we draw this Wagner matrix with the origin at the lower 
** left whereas Myers uses the origin at the upper left.  Otherwise,
** they are the same.)
**
** Let Y be the maximum y value or the number of characters in B.
** 6 in this example.  X is the maximum x value or the number of
** elements in A.  Here 7.
**
** Our goal is to find a path from (0,0) to (X,Y).  The path can
** use horizontal, vertical, or diagonal steps.  A diagonal from
** (x-1,y-1) to (x,y) is only allowed if A[x]==B[y].  A vertical
** steps corresponds to an insertion.  A horizontal step corresponds
** to a deletion.  We want to find the path with the fewest
** horizontal and vertical steps.
**
** Diagonal k consists of all points such that x-y==k.  Diagonal
** zero begins at the origin.  Diagonal 1 begins at (1,0).  
** Diagonal -1 begins at (0,1).  All diagonals move up and to the
** right at 45 degrees.  Diagonal number increase from upper left
** to lower right.
** 
** Myers matrix M is a lower right triangular matrix with indices d
** along the bottom and i vertically:
**
** 
**   i=4 |            +4  \
**     3 |         +3 +2   |
**     2 |      +2 +1  0   |- k values.   k = 2*i-d
**     1 |   +1  0 -1 -2   |
**     0 | 0 -1 -2 -3 -4  /
**       ---------------
**         0  1  2  3  4 = d
**
** Each element of the Myers matrix corresponds to a diagonal.
** The diagonal is k=2*i-d.  The diagonal values are shown
** in the template above.
**
** Each entry in M represents the end-point on a path from (0,0).
** The end-point is on diagonal k.  The value stored in M is
** q=x+y where (x,y) is the terminus of the path.  A path
** to M[d][i] will come through either M[d-1][i-1] or
** though M[d-1][i], whichever holds the largest value of q.
** If both elements hold the same value, the path comes
** through M[d-1][i-1].
**
** The value of d is the number of insertions and deletions
** made so far on the path.  M grows progressively.  So the
** size of the M matrix is proportional to d*d.  For the
** common case where A and B are similar, d will be small
** compared to X and Y so little memory is required.  The
** original Wagner algorithm requires X*Y memory, which for
** larger files (100K lines) is more memory than we have at
** hand.
*/
int *text_diff(
  Blob *pA_Blob,   /* FROM file */
  Blob *pB_Blob,   /* TO file */
  Blob *pOut,      /* Write unified diff here if not NULL */
  int nContext     /* Amount of context to unified diff */
){
  DLine *A, *B;    /* Files being compared */
  int X, Y;        /* Number of elements in A and B */
  int x, y;        /* Indices:  A[x] and B[y] */
  int szM = 0;     /* Number of rows and columns in M */
  int **M = 0;     /* Myers matrix */
  int i, d;        /* Indices on M.  M[d][i] */
  int k, q;        /* Diagonal number and distinct from (0,0) */
  int K, D;        /* The diagonal and d for the final solution */          
  int *R = 0;      /* Result vector */
  int r;           /* Loop variables */
  int go = 1;      /* Outer loop control */
  int MAX;         /* Largest of X and Y */

  /* Break the two files being diffed into individual lines.
  ** Compute hashes on each line for fast comparison.
  */
  A = break_into_lines(blob_str(pA_Blob), &X);
  B = break_into_lines(blob_str(pB_Blob), &Y);

  if( A==0 || B==0 ){
    free(A);
    free(B);
    if( pOut ){
      blob_appendf(pOut, "cannot compute difference between binary files\n");
    }
    return 0;
  }

  szM = 0;
  MAX = X>Y ? X : Y;
  for(d=0; go && d<=MAX; d++){
    if( szM<d+1 ){
      szM += szM + 10;
      M = realloc(M, sizeof(M[0])*szM);
      if( M==0 ){
        fossil_panic("out of memory");
      }
    }
    M[d] = malloc( sizeof(M[d][0])*(d+1) );
    if( M[d]==0 ){
      fossil_panic("out of memory");
    }
    for(i=0; i<=d; i++){
      k = 2*i - d;
      if( d==0 ){
        q = 0;
      }else if( i==0 ){
        q = M[d-1][0];
      }else if( i<d-1 && M[d-1][i-1] < M[d-1][i] ){
        q = M[d-1][i];
      }else{
        q = M[d-1][i-1];
      }
      x = (k + q + 1)/2;
      y = x - k;
      if( x<0 || x>X || y<0 || y>Y ){
        x = y = 0;
      }else{
        while( x<X && y<Y && same_dline(&A[x],&B[y]) ){ x++; y++; }
      }
      M[d][i] = x + y;
      DEBUG( printf("M[%d][%i] = %d  k=%d (%d,%d)\n", d, i, x+y, k, x, y); )
      if( x==X && y==Y ){
        go = 0;
        break;
      }
    }
  }
  if( d>MAX ){
    R = malloc( sizeof(R[0])*6 );
    R[0] = 0;
    R[1] = X;
    R[2] = Y;
    R[3] = 0;
    R[4] = 0;
    R[5] = 0;
  }else{
    /* Reuse M[] as follows:
    **
    **     M[d][1] = 1 if a line is inserted or 0 if a line is deleted.
    **     M[d][0] = number of lines copied after the ins or del above.
    **
    */
    D = d - 1;
    K = X - Y;
    for(d=D, i=(K+D)/2; d>0; d--){
      DEBUG( printf("d=%d i=%d\n", d, i); )
      if( i==d || (i>0 && M[d-1][i-1] > M[d-1][i]) ){
        M[d][0] = M[d][i] - M[d-1][i-1] - 1;
        M[d][1] = 0;
        i--;
      }else{
        M[d][0] = M[d][i] - M[d-1][i] - 1;
        M[d][1] = 1;
      }
    }
    
    DEBUG(
      printf("---------------\nM[0][0] = %5d\n", M[0][0]);
      for(d=1; d<=D; d++){
        printf("M[%d][0] = %5d    M[%d][1] = %d\n",d,M[d][0],d,M[d][1]);
      }
    )
    
    /* Allocate the output vector
    */
    R = malloc( sizeof(R[0])*(D+2)*3 );
    if( R==0 ){
      fossil_fatal("out of memory");
    }
    
    /* Populate the output vector
    */
    d = r = 0;
    while( d<=D ){
      int n;
      R[r++] = M[d++][0]/2;   /* COPY */
      if( d>D ){
        R[r++] = 0;
        R[r++] = 0;
        break;
      }
      if( M[d][1]==0 ){
        n = 1;
        while( M[d][0]==0 && d<D && M[d+1][1]==0 ){
          d++;
          n++;
        }
        R[r++] = n;           /* DELETE */
        if( d==D || M[d][0]>0 ){
          R[r++] = 0;         /* INSERT */
          continue;
        }
        d++;
      }else{
        R[r++] = 0;           /* DELETE */
      }
      assert( M[d][1]==1 );
      n = 1;
      while( M[d][0]==0 && d<D && M[d+1][1]==1 ){
        d++;
        n++;
      }
      R[r++] = n;            /* INSERT */
    }
    R[r++] = 0;
    R[r++] = 0;
    R[r++] = 0;
  }
    
  /* Free the Myers matrix */
  for(d=0; d<=D; d++){
    free(M[d]);
  }
  free(M);

  /* If pOut is defined, construct a unified diff into pOut and
  ** delete R
  */
  if( pOut ){
    int a = 0;    /* Index of next line in A[] */
    int b = 0;    /* Index of next line in B[] */
    int nr;       /* Number of COPY/DELETE/INSERT triples to process */
    int na, nb;   /* Number of lines shown from A and B */
    int i, j;     /* Loop counters */
    int m;        /* Number of lines to output */
    int skip;     /* Number of lines to skip */

    for(r=0; R[r+1] || R[r+2] || R[r+3]; r += 3*nr){
      /* Figure out how many triples to show in a single block */
      for(nr=1; R[r+nr*3]>0 && R[r+nr*3]<nContext*2; nr++){}
      DEBUG( printf("r=%d nr=%d\n", r, nr); )

      /* For the current block comprising nr triples, figure out
      ** how many lines of A and B are to be displayed
      */
      if( R[r]>nContext ){
        na = nb = nContext;
        skip = R[r] - nContext;
      }else{
        na = nb = R[r];
        skip = 0;
      }
      for(i=0; i<nr; i++){
        na += R[r+i*3+1];
        nb += R[r+i*3+2];
      }
      if( R[r+nr*3]>nContext ){
        na += nContext;
        nb += nContext;
      }else{
        na += R[r+nr*3];
        nb += R[r+nr*3];
      }
      for(i=1; i<nr; i++){
        na += R[r+i*3];
        nb += R[r+i*3];
      }
      blob_appendf(pOut,"@@ -%d,%d +%d,%d @@\n", a+skip+1, na, b+skip+1, nb);

      /* Show the initial common area */
      a += skip;
      b += skip;
      m = R[r] - skip;
      for(j=0; j<m; j++){
        blob_appendf(pOut," %.*s\n", A[a+j].h & LENGTH_MASK, A[a+j].z);
      }
      a += m;
      b += m;

      /* Show the differences */
      for(i=0; i<nr; i++){
        m = R[r+i*3+1];
        for(j=0; j<m; j++){
          blob_appendf(pOut,"-%.*s\n", A[a+j].h & LENGTH_MASK, A[a+j].z);
        }
        a += m;
        m = R[r+i*3+2];
        for(j=0; j<m; j++){
          blob_appendf(pOut,"+%.*s\n", B[b+j].h & LENGTH_MASK, B[b+j].z);
        }
        b += m;
        if( i<nr-1 ){
          m = R[r+i*3+3];
          for(j=0; j<m; j++){
            blob_appendf(pOut," %.*s\n", B[b+j].h & LENGTH_MASK, B[b+j].z);
          }
          b += m;
          a += m;
        }
      }

      /* Show the final common area */
      assert( nr==i );
      m = R[r+nr*3];
      if( m>nContext ) m = nContext;
      for(j=0; j<m; j++){
        blob_appendf(pOut," %.*s\n", B[b+j].h & LENGTH_MASK, B[b+j].z);
      }
    }
    free(R);
    R = 0;
  }

  /* We no longer need the A[] and B[] vectors */
  free(A);
  free(B);

  /* Return the result */
  return R;
}

/*
** COMMAND: test-rawdiff
*/
void test_rawdiff_cmd(void){
  Blob a, b;
  int r;
  int i;
  int *R;
  if( g.argc<4 ) usage("FILE1 FILE2 ...");
  blob_read_from_file(&a, g.argv[2]);
  for(i=3; i<g.argc; i++){
    if( i>3 ) printf("-------------------------------\n");
    blob_read_from_file(&b, g.argv[i]);
    R = text_diff(&a, &b, 0, 0);
    for(r=0; R[r] || R[r+1] || R[r+2]; r += 3){
      printf(" copy %4d  delete %4d  insert %4d\n", R[r], R[r+1], R[r+2]);
    }
    /* free(R); */
    blob_reset(&b);
  }
}

/*
** COMMAND: test-udiff
*/
void test_udiff_cmd(void){
  Blob a, b, out;
  if( g.argc!=4 ) usage("FILE1 FILE2");
  blob_read_from_file(&a, g.argv[2]);
  blob_read_from_file(&b, g.argv[3]);
  blob_zero(&out);
  text_diff(&a, &b, &out, 3);
  blob_write_to_file(&out, "-");
}